In trigonometry, the law of tangents is a statement about arbitrary triangles in the plane. If two sides of a triangle are (lower-case) a and b and the angles opposite those sides are (capital) A and B, then the law of tangents states
![\frac{a+b}{a-b} = \frac{\tan[\frac{1}{2}(A+B)]}{\tan[\frac{1}{2}(A-B)]}](a/../upload/math/962754f928c55f5ea637d90b9459eb9a.png)
Derivation
Start with (a + b)/(a - b). ((sin A)/a = (sin B)/b because of the law of sines):
![\frac{a+b}{a-b} = \frac{\sin(A) + \sin(B)}{\sin(A) - \sin(B)} = \frac{2\sin[\frac{1}{2}(A+B)] \cdot \cos[\frac{1}{2}(A-B)]}{2\cos[\frac{1}{2}(A+B)] \cdot \sin[\frac{1}{2}(A-B)]}](a/../upload/math/d687fde203051b42aad1add6383ec6ce.png)
- (See: Trigonometric identity)
![\frac{a+b}{a-b} = \frac{\sin[\frac{1}{2}(A+B)]}{\cos[\frac{1}{2}(A+B)]} \cdot \frac{\cos[\frac{1}{2}(A-B)]}{\sin[\frac{1}{2}(A-B)]}](a/../upload/math/449ac3e7d08838acc3b2cfc658b7606f.png)
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See also
